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Materials selection for a heat exchanger

Problem data:

90/10

70/30

P

$9,700

$16,500

n

7 yrs

10 yrs

i%

0.08

0.08

t

0.44

0.44

S

0

0

Solution:

90/10

70/30

1

-P

-$9,700

-$16,500

{t(P-S)/n}

$609.71

726.00

(P/A, i%, n)

5.206 6.710

2

{t(P-S)/n}(P/A, i%, n)

$3,174

$4,871

3

-(1-t)(X)(P/A, i%, n)

0

0

4

S(P/F, i%, n)

0

0

PW

Sum 1 + 2 + 3 + 4

-$6,526

-$11,628

(A/P, i%, n)

0.1921

0.1490

A

(PW)(A/P, i%, n)

-$1,253

-$1,733

Answer: The 90/10 copper-nickel alloy is thus a more cost economical solution